Base | Representation |
---|---|
bin | 10011100000010011010… |
… | …111011001111110100011 |
3 | 11202010200121211120111222 |
4 | 103200103113121332203 |
5 | 133430021300333141 |
6 | 2503430032525255 |
7 | 165560144650505 |
oct | 23402327317643 |
9 | 4663617746458 |
10 | 1340354699171 |
11 | 477494314a44 |
12 | 19792a0b082b |
13 | 995197b9a67 |
14 | 48c32cc7d75 |
15 | 24cebb2314b |
hex | 138135d9fa3 |
1340354699171 has 2 divisors, whose sum is σ = 1340354699172. Its totient is φ = 1340354699170.
The previous prime is 1340354699149. The next prime is 1340354699261. The reversal of 1340354699171 is 1719964530431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1340354699171 - 234 = 1323174829987 is a prime.
It is not a weakly prime, because it can be changed into another prime (1340354699111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670177349585 + 670177349586.
It is an arithmetic number, because the mean of its divisors is an integer number (670177349586).
Almost surely, 21340354699171 is an apocalyptic number.
1340354699171 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340354699171 is an equidigital number, since it uses as much as digits as its factorization.
1340354699171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2449440, while the sum is 53.
The spelling of 1340354699171 in words is "one trillion, three hundred forty billion, three hundred fifty-four million, six hundred ninety-nine thousand, one hundred seventy-one".
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