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1340354699261 is a prime number
BaseRepresentation
bin10011100000010011010…
…111011001111111111101
311202010200121211120122022
4103200103113121333331
5133430021300334021
62503430032525525
7165560144650664
oct23402327317775
94663617746568
101340354699261
11477494315016
1219792a0b08a5
13995197b9b06
1448c32cc7ddb
1524cebb231ab
hex138135d9ffd

1340354699261 has 2 divisors, whose sum is σ = 1340354699262. Its totient is φ = 1340354699260.

The previous prime is 1340354699171. The next prime is 1340354699267. The reversal of 1340354699261 is 1629964530431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1331519827225 + 8834872036 = 1153915^2 + 93994^2 .

It is an emirp because it is prime and its reverse (1629964530431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1340354699261 is a prime.

It is a super-2 number, since 2×13403546992612 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340354699267) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670177349630 + 670177349631.

It is an arithmetic number, because the mean of its divisors is an integer number (670177349631).

Almost surely, 21340354699261 is an apocalyptic number.

It is an amenable number.

1340354699261 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340354699261 is an equidigital number, since it uses as much as digits as its factorization.

1340354699261 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4199040, while the sum is 53.

The spelling of 1340354699261 in words is "one trillion, three hundred forty billion, three hundred fifty-four million, six hundred ninety-nine thousand, two hundred sixty-one".