13403624813 has 4 divisors (see below), whose sum is σ = 13404127008. Its totient is φ = 13403122620.

The previous prime is 13403624807. The next prime is 13403624873. The reversal of 13403624813 is 31842630431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31842630431 = 29 ⋅1098021739.

It is a cyclic number.

It is not a de Polignac number, because 13403624813 - 2⁴ = 13403624797 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13403624873) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 208673 + ... + 265238.

It is an arithmetic number, because the mean of its divisors is an integer number (3351031752).

Almost surely, 2^13403624813 is an apocalyptic number.

It is an amenable number.

13403624813 is a deficient number, since it is larger than the sum of its proper divisors (502195).

13403624813 is an equidigital number, since it uses as much as digits as its factorization.

13403624813 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 502194.

The product of its (nonzero) digits is 41472, while the sum is 35.

The spelling of 13403624813 in words is "thirteen billion, four hundred three million, six hundred twenty-four thousand, eight hundred thirteen".