Base | Representation |
---|---|
bin | 11000111101111000… |
… | …01101011011100111 |
3 | 1021121010222212001101 |
4 | 30132330031123213 |
5 | 204422411031043 |
6 | 10054022140531 |
7 | 653110065046 |
oct | 143674153347 |
9 | 37533885041 |
10 | 13404002023 |
11 | 5759234125 |
12 | 2720b81747 |
13 | 1357cb4a59 |
14 | 91229255d |
15 | 536b5624d |
hex | 31ef0d6e7 |
13404002023 has 4 divisors (see below), whose sum is σ = 13452392200. Its totient is φ = 13355611848.
The previous prime is 13404001993. The next prime is 13404002069. The reversal of 13404002023 is 32020040431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32020040431 = 8269 ⋅3872299.
It is a cyclic number.
It is not a de Polignac number, because 13404002023 - 213 = 13403993831 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13404000023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24194673 + ... + 24195226.
It is an arithmetic number, because the mean of its divisors is an integer number (3363098050).
Almost surely, 213404002023 is an apocalyptic number.
13404002023 is a deficient number, since it is larger than the sum of its proper divisors (48390177).
13404002023 is an equidigital number, since it uses as much as digits as its factorization.
13404002023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 48390176.
The product of its (nonzero) digits is 576, while the sum is 19.
Adding to 13404002023 its reverse (32020040431), we get a palindrome (45424042454).
The spelling of 13404002023 in words is "thirteen billion, four hundred four million, two thousand, twenty-three".
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