Base | Representation |
---|---|
bin | 11000111101111000… |
… | …10011010110011110 |
3 | 1021121011001002022102 |
4 | 30132330103112132 |
5 | 204422412320040 |
6 | 10054022445102 |
7 | 653110225535 |
oct | 143674232636 |
9 | 37534032272 |
10 | 13404026270 |
11 | 5759250368 |
12 | 2720b93792 |
13 | 1357cc2abb |
14 | 91229b31c |
15 | 536b5d515 |
hex | 31ef1359e |
13404026270 has 32 divisors (see below), whose sum is σ = 24867470880. Its totient is φ = 5198722560.
The previous prime is 13404026269. The next prime is 13404026281. The reversal of 13404026270 is 7262040431.
It is a super-2 number, since 2×134040262702 (a number of 21 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 33455 + ... + 167114.
It is an arithmetic number, because the mean of its divisors is an integer number (777108465).
Almost surely, 213404026270 is an apocalyptic number.
13404026270 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13404026270 is a deficient number, since it is larger than the sum of its proper divisors (11463444610).
13404026270 is a wasteful number, since it uses less digits than its factorization.
13404026270 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 200780.
The product of its (nonzero) digits is 8064, while the sum is 29.
The spelling of 13404026270 in words is "thirteen billion, four hundred four million, twenty-six thousand, two hundred seventy".
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