1340403102131 has 4 divisors (see below), whose sum is σ = 1340533616064. Its totient is φ = 1340272588200.

The previous prime is 1340403102109. The next prime is 1340403102179. The reversal of 1340403102131 is 1312013040431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1340403102131 - 2¹⁸ = 1340402839987 is a prime.

It is a super-2 number, since 2×1340403102131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1340403102097 and 1340403102106.

It is not an unprimeable number, because it can be changed into a prime (1340403102431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65241560 + ... + 65262101.

It is an arithmetic number, because the mean of its divisors is an integer number (335133404016).

Almost surely, 2^{1340403102131} is an apocalyptic number.

1340403102131 is a deficient number, since it is larger than the sum of its proper divisors (130513933).

1340403102131 is a wasteful number, since it uses less digits than its factorization.

1340403102131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 130513932.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 1340403102131 its reverse (1312013040431), we get a palindrome (2652416142562).

The spelling of 1340403102131 in words is "one trillion, three hundred forty billion, four hundred three million, one hundred two thousand, one hundred thirty-one".