1340403403501 has 4 divisors (see below), whose sum is σ = 1340408420032. Its totient is φ = 1340398386972.

The previous prime is 1340403403489. The next prime is 1340403403529. The reversal of 1340403403501 is 1053043040431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1340403403501 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1340403403501.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340413403501) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2083491 + ... + 2649856.

It is an arithmetic number, because the mean of its divisors is an integer number (335102105008).

Almost surely, 2^{1340403403501} is an apocalyptic number.

It is an amenable number.

1340403403501 is a deficient number, since it is larger than the sum of its proper divisors (5016531).

1340403403501 is an equidigital number, since it uses as much as digits as its factorization.

1340403403501 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5016530.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 1340403403501 its reverse (1053043040431), we get a palindrome (2393446443932).

The spelling of 1340403403501 in words is "one trillion, three hundred forty billion, four hundred three million, four hundred three thousand, five hundred one".