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134041153 is a prime number
BaseRepresentation
bin1111111110101…
…00111001000001
3100100012222220011
413333110321001
5233303304103
621144544521
73215221351
oct777247101
9310188804
10134041153
1169732114
1238a82141
1321a01cbc
1413b32b61
15bb7ad6d
hex7fd4e41

134041153 has 2 divisors, whose sum is σ = 134041154. Its totient is φ = 134041152.

The previous prime is 134041151. The next prime is 134041163. The reversal of 134041153 is 351140431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 85988529 + 48052624 = 9273^2 + 6932^2 .

It is a cyclic number.

It is not a de Polignac number, because 134041153 - 21 = 134041151 is a prime.

Together with 134041151, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (134041151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67020576 + 67020577.

It is an arithmetic number, because the mean of its divisors is an integer number (67020577).

Almost surely, 2134041153 is an apocalyptic number.

It is an amenable number.

134041153 is a deficient number, since it is larger than the sum of its proper divisors (1).

134041153 is an equidigital number, since it uses as much as digits as its factorization.

134041153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 22.

The square root of 134041153 is about 11577.6143052012. The cubic root of 134041153 is about 511.7753747433.

Adding to 134041153 its reverse (351140431), we get a palindrome (485181584).

The spelling of 134041153 in words is "one hundred thirty-four million, forty-one thousand, one hundred fifty-three".