Base | Representation |
---|---|
bin | 111110011010101111… |
… | …0011010111110101100 |
3 | 110210222120002002222220 |
4 | 1330311132122332230 |
5 | 4144004013402302 |
6 | 141324435035340 |
7 | 12453444001563 |
oct | 1746536327654 |
9 | 423876062886 |
10 | 134041153452 |
11 | 51934811578 |
12 | 21b8a13bb50 |
13 | c8421a4aab |
14 | 66b8092bda |
15 | 3747a174bc |
hex | 1f3579afac |
134041153452 has 12 divisors (see below), whose sum is σ = 312762691416. Its totient is φ = 44680384480.
The previous prime is 134041153423. The next prime is 134041153471. The reversal of 134041153452 is 254351140431.
It is a tau number, because it is divible by the number of its divisors (12).
It is a super-2 number, since 2×1340411534522 (a number of 23 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5585048049 + ... + 5585048072.
It is an arithmetic number, because the mean of its divisors is an integer number (26063557618).
Almost surely, 2134041153452 is an apocalyptic number.
134041153452 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
134041153452 is an abundant number, since it is smaller than the sum of its proper divisors (178721537964).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134041153452 is a wasteful number, since it uses less digits than its factorization.
134041153452 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11170096128 (or 11170096126 counting only the distinct ones).
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 134041153452 its reverse (254351140431), we get a palindrome (388392293883).
The spelling of 134041153452 in words is "one hundred thirty-four billion, forty-one million, one hundred fifty-three thousand, four hundred fifty-two".
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