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134041153452 = 22311170096121
BaseRepresentation
bin111110011010101111…
…0011010111110101100
3110210222120002002222220
41330311132122332230
54144004013402302
6141324435035340
712453444001563
oct1746536327654
9423876062886
10134041153452
1151934811578
1221b8a13bb50
13c8421a4aab
1466b8092bda
153747a174bc
hex1f3579afac

134041153452 has 12 divisors (see below), whose sum is σ = 312762691416. Its totient is φ = 44680384480.

The previous prime is 134041153423. The next prime is 134041153471. The reversal of 134041153452 is 254351140431.

It is a tau number, because it is divible by the number of its divisors (12).

It is a super-2 number, since 2×1340411534522 (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5585048049 + ... + 5585048072.

It is an arithmetic number, because the mean of its divisors is an integer number (26063557618).

Almost surely, 2134041153452 is an apocalyptic number.

134041153452 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

134041153452 is an abundant number, since it is smaller than the sum of its proper divisors (178721537964).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134041153452 is a wasteful number, since it uses less digits than its factorization.

134041153452 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11170096128 (or 11170096126 counting only the distinct ones).

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 134041153452 its reverse (254351140431), we get a palindrome (388392293883).

The spelling of 134041153452 in words is "one hundred thirty-four billion, forty-one million, one hundred fifty-three thousand, four hundred fifty-two".

Divisors: 1 2 3 4 6 12 11170096121 22340192242 33510288363 44680384484 67020576726 134041153452