1340412113 has 2 divisors, whose sum is σ = 1340412114. Its totient is φ = 1340412112.

The previous prime is 1340412097. The next prime is 1340412127. The reversal of 1340412113 is 3112140431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1081620544 + 258791569 = 32888^2 + 16087^2 .

It is an emirp because it is prime and its reverse (3112140431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1340412113 - 2⁴ = 1340412097 is a prime.

It is not a weakly prime, because it can be changed into another prime (1340412313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670206056 + 670206057.

It is an arithmetic number, because the mean of its divisors is an integer number (670206057).

Almost surely, 2^1340412113 is an apocalyptic number.

It is an amenable number.

1340412113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340412113 is an equidigital number, since it uses as much as digits as its factorization.

1340412113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 20.

The square root of 1340412113 is about 36611.6390373335. The cubic root of 1340412113 is about 1102.5867807045.

Adding to 1340412113 its reverse (3112140431), we get a palindrome (4452552544).

The spelling of 1340412113 in words is "one billion, three hundred forty million, four hundred twelve thousand, one hundred thirteen".