13404125333 has 4 divisors (see below), whose sum is σ = 13405219488. Its totient is φ = 13403031180.

The previous prime is 13404125297. The next prime is 13404125341. The reversal of 13404125333 is 33352140431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13404125333 - 2¹⁰ = 13404124309 is a prime.

It is a super-3 number, since 3×13404125333³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13404125296 and 13404125305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13404125353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 528491 + ... + 553272.

It is an arithmetic number, because the mean of its divisors is an integer number (3351304872).

Almost surely, 2^13404125333 is an apocalyptic number.

It is an amenable number.

13404125333 is a deficient number, since it is larger than the sum of its proper divisors (1094155).

13404125333 is a wasteful number, since it uses less digits than its factorization.

13404125333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1094154.

The product of its (nonzero) digits is 12960, while the sum is 29.

Adding to 13404125333 its reverse (33352140431), we get a palindrome (46756265764).

The spelling of 13404125333 in words is "thirteen billion, four hundred four million, one hundred twenty-five thousand, three hundred thirty-three".