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13404134455132 = 225875708745509
BaseRepresentation
bin1100001100001110010010…
…1011000011011101011100
31202110102102011202222111011
43003003210223003131130
53224103131410031012
644301435132305004
72552262642653431
oct303034453033534
952412364688434
1013404134455132
1142a8730500463
121605989612164
13763009a336c5
14344a9933bb88
15183a140141a7
hexc30e4ac375c

13404134455132 has 12 divisors (see below), whose sum is σ = 23497196519160. Its totient is φ = 6690649735376.

The previous prime is 13404134455099. The next prime is 13404134455139. The reversal of 13404134455132 is 23155443140431.

It is a super-2 number, since 2×134041344551322 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13404134455139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2854370407 + ... + 2854375102.

It is an arithmetic number, because the mean of its divisors is an integer number (1958099709930).

Almost surely, 213404134455132 is an apocalyptic number.

It is an amenable number.

13404134455132 is a deficient number, since it is larger than the sum of its proper divisors (10093062064028).

13404134455132 is a wasteful number, since it uses less digits than its factorization.

13404134455132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5708746100 (or 5708746098 counting only the distinct ones).

The product of its (nonzero) digits is 345600, while the sum is 40.

Adding to 13404134455132 its reverse (23155443140431), we get a palindrome (36559577595563).

The spelling of 13404134455132 in words is "thirteen trillion, four hundred four billion, one hundred thirty-four million, four hundred fifty-five thousand, one hundred thirty-two".

Divisors: 1 2 4 587 1174 2348 5708745509 11417491018 22834982036 3351033613783 6702067227566 13404134455132