Base | Representation |
---|---|
bin | 1100001100001110010100… |
… | …1001001001001110001111 |
3 | 1202110102102201121201200110 |
4 | 3003003211021021032033 |
5 | 3224103140414434210 |
6 | 44301440013331103 |
7 | 2552263100005332 |
oct | 303034511111617 |
9 | 52412381551613 |
10 | 13404142343055 |
11 | 42a87349a8802 |
12 | 1605990196a93 |
13 | 76300b565b09 |
14 | 344a9a3d2619 |
15 | 183a14a71420 |
hex | c30e524938f |
13404142343055 has 16 divisors (see below), whose sum is σ = 21446673467904. Its totient is φ = 7148860676640.
The previous prime is 13404142343051. The next prime is 13404142343063. The reversal of 13404142343055 is 55034324140431.
It is not a de Polignac number, because 13404142343055 - 22 = 13404142343051 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13404142343051) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12002902 + ... + 13072028.
It is an arithmetic number, because the mean of its divisors is an integer number (1340417091744).
Almost surely, 213404142343055 is an apocalyptic number.
13404142343055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13404142343055 is a deficient number, since it is larger than the sum of its proper divisors (8042531124849).
13404142343055 is a wasteful number, since it uses less digits than its factorization.
13404142343055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1904966.
The product of its (nonzero) digits is 345600, while the sum is 39.
Adding to 13404142343055 its reverse (55034324140431), we get a palindrome (68438466483486).
The spelling of 13404142343055 in words is "thirteen trillion, four hundred four billion, one hundred forty-two million, three hundred forty-three thousand, fifty-five".
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