Base | Representation |
---|---|
bin | 1100001100001110101100… |
… | …0001100010101001011101 |
3 | 1202110102200121021200212111 |
4 | 3003003223001202221131 |
5 | 3224103341144411331 |
6 | 44301453500234021 |
7 | 2552265405461653 |
oct | 303035301425135 |
9 | 52412617250774 |
10 | 13404241013341 |
11 | 42a87856711a2 |
12 | 16059b923b911 |
13 | 763025b322b9 |
14 | 344aa9558dd3 |
15 | 183a1d561db1 |
hex | c30eb062a5d |
13404241013341 has 2 divisors, whose sum is σ = 13404241013342. Its totient is φ = 13404241013340.
The previous prime is 13404241013269. The next prime is 13404241013417. The reversal of 13404241013341 is 14331014240431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13400387707716 + 3853305625 = 3660654^2 + 62075^2 .
It is a cyclic number.
It is not a de Polignac number, because 13404241013341 - 215 = 13404240980573 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13404241313341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702120506670 + 6702120506671.
It is an arithmetic number, because the mean of its divisors is an integer number (6702120506671).
Almost surely, 213404241013341 is an apocalyptic number.
It is an amenable number.
13404241013341 is a deficient number, since it is larger than the sum of its proper divisors (1).
13404241013341 is an equidigital number, since it uses as much as digits as its factorization.
13404241013341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 13404241013341 its reverse (14331014240431), we get a palindrome (27735255253772).
The spelling of 13404241013341 in words is "thirteen trillion, four hundred four billion, two hundred forty-one million, thirteen thousand, three hundred forty-one".
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