13404244211 has 2 divisors, whose sum is σ = 13404244212. Its totient is φ = 13404244210.

The previous prime is 13404244181. The next prime is 13404244213. The reversal of 13404244211 is 11244240431.

It is a strong prime.

It is an emirp because it is prime and its reverse (11244240431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13404244211 - 2¹⁰ = 13404243187 is a prime.

It is a Sophie Germain prime.

Together with 13404244213, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13404244213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702122105 + 6702122106.

It is an arithmetic number, because the mean of its divisors is an integer number (6702122106).

Almost surely, 2^13404244211 is an apocalyptic number.

13404244211 is a deficient number, since it is larger than the sum of its proper divisors (1).

13404244211 is an equidigital number, since it uses as much as digits as its factorization.

13404244211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3072, while the sum is 26.

Adding to 13404244211 its reverse (11244240431), we get a palindrome (24648484642).

The spelling of 13404244211 in words is "thirteen billion, four hundred four million, two hundred forty-four thousand, two hundred eleven".