Base | Representation |
---|---|
bin | 10011100000010111111… |
… | …100011111110000000011 |
3 | 11202010212222102000222200 |
4 | 103200113330133300003 |
5 | 133430200432443021 |
6 | 2503441415404243 |
7 | 165562100010156 |
oct | 23402774376003 |
9 | 4663788360880 |
10 | 1340431531011 |
11 | 477523721931 |
12 | 19794b983683 |
13 | 9952c6ab0a1 |
14 | 48c3d1a7c9d |
15 | 24d0374d126 |
hex | 13817f1fc03 |
1340431531011 has 12 divisors (see below), whose sum is σ = 1956139486392. Its totient is φ = 884408432256.
The previous prime is 1340431531001. The next prime is 1340431531169. The reversal of 1340431531011 is 1101351340431.
1340431531011 is a `hidden beast` number, since 1 + 3 + 404 + 3 + 153 + 101 + 1 = 666.
It is a de Polignac number, because none of the positive numbers 2k-1340431531011 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1340431531001) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 767714781 + ... + 767716526.
It is an arithmetic number, because the mean of its divisors is an integer number (163011623866).
Almost surely, 21340431531011 is an apocalyptic number.
1340431531011 is a deficient number, since it is larger than the sum of its proper divisors (615707955381).
1340431531011 is a wasteful number, since it uses less digits than its factorization.
1340431531011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1535431410 (or 1535431407 counting only the distinct ones).
The product of its (nonzero) digits is 2160, while the sum is 27.
Adding to 1340431531011 its reverse (1101351340431), we get a palindrome (2441782871442).
The spelling of 1340431531011 in words is "one trillion, three hundred forty billion, four hundred thirty-one million, five hundred thirty-one thousand, eleven".
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