Base | Representation |
---|---|
bin | 111110011010110011… |
… | …0011000101000111101 |
3 | 110210222201000011121021 |
4 | 1330311212120220331 |
5 | 4144010032203041 |
6 | 141324551504141 |
7 | 12453500515024 |
oct | 1746546305075 |
9 | 423881004537 |
10 | 134043241021 |
11 | 51935a07a38 |
12 | 21b8a988051 |
13 | c842756041 |
14 | 66b84778bb |
15 | 3747ccacd1 |
hex | 1f35998a3d |
134043241021 has 4 divisors (see below), whose sum is σ = 134087940000. Its totient is φ = 133998542044.
The previous prime is 134043240979. The next prime is 134043241049. The reversal of 134043241021 is 120142340431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 120142340431 = 43 ⋅2794007917.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134043241021 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134043241921) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22344991 + ... + 22350988.
It is an arithmetic number, because the mean of its divisors is an integer number (33521985000).
Almost surely, 2134043241021 is an apocalyptic number.
It is an amenable number.
134043241021 is a deficient number, since it is larger than the sum of its proper divisors (44698979).
134043241021 is an equidigital number, since it uses as much as digits as its factorization.
134043241021 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 44698978.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 134043241021 its reverse (120142340431), we get a palindrome (254185581452).
The spelling of 134043241021 in words is "one hundred thirty-four billion, forty-three million, two hundred forty-one thousand, twenty-one".
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