1340433454340 has 24 divisors (see below), whose sum is σ = 2818782238272. Its totient is φ = 535435860960.

The previous prime is 1340433454307. The next prime is 1340433454351. The reversal of 1340433454340 is 434543340431.

It is a junction number, because it is equal to n+sod(n) for n = 1340433454294 and 1340433454303.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 46080146 + ... + 46109225.

It is an arithmetic number, because the mean of its divisors is an integer number (117449259928).

Almost surely, 2^{1340433454340} is an apocalyptic number.

1340433454340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1340433454340 is an abundant number, since it is smaller than the sum of its proper divisors (1478348783932).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1340433454340 is a wasteful number, since it uses less digits than its factorization.

1340433454340 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 92190107 (or 92190105 counting only the distinct ones).

The product of its (nonzero) digits is 414720, while the sum is 38.

Adding to 1340433454340 its reverse (434543340431), we get a palindrome (1774976794771).

The spelling of 1340433454340 in words is "one trillion, three hundred forty billion, four hundred thirty-three million, four hundred fifty-four thousand, three hundred forty".