1340433680249 has 2 divisors, whose sum is σ = 1340433680250. Its totient is φ = 1340433680248.

The previous prime is 1340433680203. The next prime is 1340433680251. The reversal of 1340433680249 is 9420863340431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 761779840000 + 578653840249 = 872800^2 + 760693^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1340433680249 is a prime.

It is a super-2 number, since 2×1340433680249² (a number of 25 digits) contains 22 as substring.

Together with 1340433680251, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1340433680279) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670216840124 + 670216840125.

It is an arithmetic number, because the mean of its divisors is an integer number (670216840125).

Almost surely, 2^{1340433680249} is an apocalyptic number.

It is an amenable number.

1340433680249 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340433680249 is an equidigital number, since it uses as much as digits as its factorization.

1340433680249 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1492992, while the sum is 47.

The spelling of 1340433680249 in words is "one trillion, three hundred forty billion, four hundred thirty-three million, six hundred eighty thousand, two hundred forty-nine".