Base | Representation |
---|---|
bin | 111110011010110011… |
… | …1000100100101101001 |
3 | 110210222201100022112101 |
4 | 1330311213010211221 |
5 | 4144010103433113 |
6 | 141324555413401 |
7 | 12453502164604 |
oct | 1746547044551 |
9 | 423881308471 |
10 | 134043421033 |
11 | 51936020205 |
12 | 21b8aa54261 |
13 | c8427b9c62 |
14 | 66b84c333b |
15 | 3747d142dd |
hex | 1f359c4969 |
134043421033 has 2 divisors, whose sum is σ = 134043421034. Its totient is φ = 134043421032.
The previous prime is 134043421019. The next prime is 134043421049. The reversal of 134043421033 is 330124340431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 109854462249 + 24188958784 = 331443^2 + 155528^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134043421033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134043420992 and 134043421010.
It is not a weakly prime, because it can be changed into another prime (134043421073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67021710516 + 67021710517.
It is an arithmetic number, because the mean of its divisors is an integer number (67021710517).
Almost surely, 2134043421033 is an apocalyptic number.
It is an amenable number.
134043421033 is a deficient number, since it is larger than the sum of its proper divisors (1).
134043421033 is an equidigital number, since it uses as much as digits as its factorization.
134043421033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 134043421033 its reverse (330124340431), we get a palindrome (464167761464).
The spelling of 134043421033 in words is "one hundred thirty-four billion, forty-three million, four hundred twenty-one thousand, thirty-three".
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