134043421049 has 2 divisors, whose sum is σ = 134043421050. Its totient is φ = 134043421048.

The previous prime is 134043421033. The next prime is 134043421051. The reversal of 134043421049 is 940124340431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129830502400 + 4212918649 = 360320^2 + 64907^2 .

It is a cyclic number.

It is not a de Polignac number, because 134043421049 - 2⁴ = 134043421033 is a prime.

Together with 134043421051, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (134043421019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67021710524 + 67021710525.

It is an arithmetic number, because the mean of its divisors is an integer number (67021710525).

Almost surely, 2^134043421049 is an apocalyptic number.

It is an amenable number.

134043421049 is a deficient number, since it is larger than the sum of its proper divisors (1).

134043421049 is an equidigital number, since it uses as much as digits as its factorization.

134043421049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 35.

The spelling of 134043421049 in words is "one hundred thirty-four billion, forty-three million, four hundred twenty-one thousand, forty-nine".