134043421321 has 4 divisors (see below), whose sum is σ = 136572542532. Its totient is φ = 131514300112.

The previous prime is 134043421313. The next prime is 134043421333. The reversal of 134043421321 is 123124340431.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 123124340431 = 1229 ⋅100182539.

It can be written as a sum of positive squares in 2 ways, for example, as 107004223225 + 27039198096 = 327115^2 + 164436^2 .

It is a cyclic number.

It is not a de Polignac number, because 134043421321 - 2³ = 134043421313 is a prime.

It is a super-3 number, since 3×134043421321³ (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 134043421321.

It is not an unprimeable number, because it can be changed into a prime (134043421301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1264560526 + ... + 1264560631.

It is an arithmetic number, because the mean of its divisors is an integer number (34143135633).

Almost surely, 2^134043421321 is an apocalyptic number.

It is an amenable number.

134043421321 is a deficient number, since it is larger than the sum of its proper divisors (2529121211).

134043421321 is an equidigital number, since it uses as much as digits as its factorization.

134043421321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2529121210.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 134043421321 its reverse (123124340431), we get a palindrome (257167761752).

The spelling of 134043421321 in words is "one hundred thirty-four billion, forty-three million, four hundred twenty-one thousand, three hundred twenty-one".