Base | Representation |
---|---|
bin | 1100001100001111000100… |
… | …0111000001011000001000 |
3 | 1202110102221201101220120122 |
4 | 3003003301013001120020 |
5 | 3224104043314110344 |
6 | 44301511544442412 |
7 | 2552301055351160 |
oct | 303036107013010 |
9 | 52412851356518 |
10 | 13404343113224 |
11 | 42a8828267368 |
12 | 1605a27479408 |
13 | 76304102c82b |
14 | 344ab8d355a0 |
15 | 183a274cdaee |
hex | c30f11c1608 |
13404343113224 has 16 divisors (see below), whose sum is σ = 28723592385600. Its totient is φ = 5744718477072.
The previous prime is 13404343113211. The next prime is 13404343113229. The reversal of 13404343113224 is 42231134340431.
It is not an unprimeable number, because it can be changed into a prime (13404343113229) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 119681634884 + ... + 119681634995.
It is an arithmetic number, because the mean of its divisors is an integer number (1795224524100).
Almost surely, 213404343113224 is an apocalyptic number.
13404343113224 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
13404343113224 is an abundant number, since it is smaller than the sum of its proper divisors (15319249272376).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13404343113224 is a wasteful number, since it uses less digits than its factorization.
13404343113224 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 239363269892 (or 239363269888 counting only the distinct ones).
The product of its (nonzero) digits is 82944, while the sum is 35.
Adding to 13404343113224 its reverse (42231134340431), we get a palindrome (55635477453655).
The spelling of 13404343113224 in words is "thirteen trillion, four hundred four billion, three hundred forty-three million, one hundred thirteen thousand, two hundred twenty-four".
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