Base | Representation |
---|---|
bin | 1111111110101… |
… | …01011100111011 |
3 | 100100020010001021 |
4 | 13333111130323 |
5 | 233303342301 |
6 | 21145003311 |
7 | 3215231143 |
oct | 777253473 |
9 | 310203037 |
10 | 134043451 |
11 | 69733913 |
12 | 38a83537 |
13 | 21a03069 |
14 | 13b33923 |
15 | bb7b8a1 |
hex | 7fd573b |
134043451 has 2 divisors, whose sum is σ = 134043452. Its totient is φ = 134043450.
The previous prime is 134043449. The next prime is 134043467. The reversal of 134043451 is 154340431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134043451 - 21 = 134043449 is a prime.
Together with 134043449, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (134043431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67021725 + 67021726.
It is an arithmetic number, because the mean of its divisors is an integer number (67021726).
Almost surely, 2134043451 is an apocalyptic number.
134043451 is a deficient number, since it is larger than the sum of its proper divisors (1).
134043451 is an equidigital number, since it uses as much as digits as its factorization.
134043451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 25.
The square root of 134043451 is about 11577.7135480197. The cubic root of 134043451 is about 511.7782993503.
Adding to 134043451 its reverse (154340431), we get a palindrome (288383882).
The spelling of 134043451 in words is "one hundred thirty-four million, forty-three thousand, four hundred fifty-one".
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