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134047223 = 197055117
BaseRepresentation
bin1111111110101…
…10010111110111
3100100020022012222
413333112113313
5233304002343
621145032555
73215245142
oct777262767
9310208188
10134047223
1169736732
1238a8575b
1321a049ab
1413b35059
15bb7ca68
hex7fd65f7

134047223 has 4 divisors (see below), whose sum is σ = 141102360. Its totient is φ = 126992088.

The previous prime is 134047217. The next prime is 134047231. The reversal of 134047223 is 322740431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134047223 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 134047192 and 134047201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134047253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3527540 + ... + 3527577.

It is an arithmetic number, because the mean of its divisors is an integer number (35275590).

Almost surely, 2134047223 is an apocalyptic number.

134047223 is a deficient number, since it is larger than the sum of its proper divisors (7055137).

134047223 is an equidigital number, since it uses as much as digits as its factorization.

134047223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7055136.

The product of its (nonzero) digits is 4032, while the sum is 26.

The square root of 134047223 is about 11577.8764460500. The cubic root of 134047223 is about 511.7830998078.

Adding to 134047223 its reverse (322740431), we get a palindrome (456787654).

The spelling of 134047223 in words is "one hundred thirty-four million, forty-seven thousand, two hundred twenty-three".

Divisors: 1 19 7055117 134047223