1340481110441 has 8 divisors (see below), whose sum is σ = 1464784344000. Its totient is φ = 1216584762640.

The previous prime is 1340481110377. The next prime is 1340481110473. The reversal of 1340481110441 is 1440111840431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1340481110441 - 2⁶ = 1340481110377 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1340481110398 and 1340481110407.

It is not an unprimeable number, because it can be changed into a prime (1340481113441) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 101714546 + ... + 101727723.

It is an arithmetic number, because the mean of its divisors is an integer number (183098043000).

Almost surely, 2^{1340481110441} is an apocalyptic number.

1340481110441 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1340481110441 is a deficient number, since it is larger than the sum of its proper divisors (124303233559).

1340481110441 is a wasteful number, since it uses less digits than its factorization.

1340481110441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 203442879.

The product of its (nonzero) digits is 6144, while the sum is 32.

Adding to 1340481110441 its reverse (1440111840431), we get a palindrome (2780592950872).

The spelling of 1340481110441 in words is "one trillion, three hundred forty billion, four hundred eighty-one million, one hundred ten thousand, four hundred forty-one".