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1340500153 is a prime number
BaseRepresentation
bin100111111100110…
…0110100010111001
310110102101110111211
41033321212202321
510221132001103
6341003323121
745135030466
oct11771464271
93412343454
101340500153
1162874a673
12314b204a1
13184948375
14ca06466d
157ca4036d
hex4fe668b9

1340500153 has 2 divisors, whose sum is σ = 1340500154. Its totient is φ = 1340500152.

The previous prime is 1340500061. The next prime is 1340500157. The reversal of 1340500153 is 3510050431.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 904024489 + 436475664 = 30067^2 + 20892^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1340500153 is a prime.

It is not a weakly prime, because it can be changed into another prime (1340500157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670250076 + 670250077.

It is an arithmetic number, because the mean of its divisors is an integer number (670250077).

Almost surely, 21340500153 is an apocalyptic number.

It is an amenable number.

1340500153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340500153 is an equidigital number, since it uses as much as digits as its factorization.

1340500153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 900, while the sum is 22.

The square root of 1340500153 is about 36612.8413674765. The cubic root of 1340500153 is about 1102.6109199509.

Adding to 1340500153 its reverse (3510050431), we get a palindrome (4850550584).

The spelling of 1340500153 in words is "one billion, three hundred forty million, five hundred thousand, one hundred fifty-three".