Base | Representation |
---|---|
bin | 11000111110000001… |
… | …10101100110001111 |
3 | 1021121020021111002212 |
4 | 30133000311212033 |
5 | 204423213340434 |
6 | 10054104141035 |
7 | 653123306552 |
oct | 143700654617 |
9 | 37536244085 |
10 | 13405215119 |
11 | 575999258a |
12 | 272146777b |
13 | 135831ac6a |
14 | 9124ca699 |
15 | 536ce58ce |
hex | 31f03598f |
13405215119 has 2 divisors, whose sum is σ = 13405215120. Its totient is φ = 13405215118.
The previous prime is 13405215091. The next prime is 13405215133. The reversal of 13405215119 is 91151250431.
It is a strong prime.
It is an emirp because it is prime and its reverse (91151250431) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13405215119 is a prime.
It is a super-2 number, since 2×134052151192 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13405211119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702607559 + 6702607560.
It is an arithmetic number, because the mean of its divisors is an integer number (6702607560).
Almost surely, 213405215119 is an apocalyptic number.
13405215119 is a deficient number, since it is larger than the sum of its proper divisors (1).
13405215119 is an equidigital number, since it uses as much as digits as its factorization.
13405215119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 32.
The spelling of 13405215119 in words is "thirteen billion, four hundred five million, two hundred fifteen thousand, one hundred nineteen".
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