Base | Representation |
---|---|
bin | 11000111110000010… |
… | …01110000001000011 |
3 | 1021121020110120022022 |
4 | 30133001032001003 |
5 | 204423230041024 |
6 | 10054110232055 |
7 | 653124204266 |
oct | 143701160103 |
9 | 37536416268 |
10 | 13405315139 |
11 | 5759a50747 |
12 | 27214b562b |
13 | 1358354648 |
14 | 912514cdd |
15 | 536d1535e |
hex | 31f04e043 |
13405315139 has 2 divisors, whose sum is σ = 13405315140. Its totient is φ = 13405315138.
The previous prime is 13405315117. The next prime is 13405315153. The reversal of 13405315139 is 93151350431.
It is a strong prime.
It is an emirp because it is prime and its reverse (93151350431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13405315139 - 28 = 13405314883 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 13405315099 and 13405315108.
It is not a weakly prime, because it can be changed into another prime (13405315159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702657569 + 6702657570.
It is an arithmetic number, because the mean of its divisors is an integer number (6702657570).
Almost surely, 213405315139 is an apocalyptic number.
13405315139 is a deficient number, since it is larger than the sum of its proper divisors (1).
13405315139 is an equidigital number, since it uses as much as digits as its factorization.
13405315139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24300, while the sum is 35.
The spelling of 13405315139 in words is "thirteen billion, four hundred five million, three hundred fifteen thousand, one hundred thirty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •