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13405315153 is a prime number
BaseRepresentation
bin11000111110000010…
…01110000001010001
31021121020110120022211
430133001032001101
5204423230041103
610054110232121
7653124204316
oct143701160121
937536416284
1013405315153
115759a5075a
1227214b5641
131358354659
14912514d0d
15536d1536d
hex31f04e051

13405315153 has 2 divisors, whose sum is σ = 13405315154. Its totient is φ = 13405315152.

The previous prime is 13405315139. The next prime is 13405315159. The reversal of 13405315153 is 35151350431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12637581889 + 767733264 = 112417^2 + 27708^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13405315153 is a prime.

It is not a weakly prime, because it can be changed into another prime (13405315159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702657576 + 6702657577.

It is an arithmetic number, because the mean of its divisors is an integer number (6702657577).

Almost surely, 213405315153 is an apocalyptic number.

It is an amenable number.

13405315153 is a deficient number, since it is larger than the sum of its proper divisors (1).

13405315153 is an equidigital number, since it uses as much as digits as its factorization.

13405315153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 13405315153 its reverse (35151350431), we get a palindrome (48556665584).

The spelling of 13405315153 in words is "thirteen billion, four hundred five million, three hundred fifteen thousand, one hundred fifty-three".