Base | Representation |
---|---|
bin | 11000111110000010… |
… | …01110000001010001 |
3 | 1021121020110120022211 |
4 | 30133001032001101 |
5 | 204423230041103 |
6 | 10054110232121 |
7 | 653124204316 |
oct | 143701160121 |
9 | 37536416284 |
10 | 13405315153 |
11 | 5759a5075a |
12 | 27214b5641 |
13 | 1358354659 |
14 | 912514d0d |
15 | 536d1536d |
hex | 31f04e051 |
13405315153 has 2 divisors, whose sum is σ = 13405315154. Its totient is φ = 13405315152.
The previous prime is 13405315139. The next prime is 13405315159. The reversal of 13405315153 is 35151350431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12637581889 + 767733264 = 112417^2 + 27708^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13405315153 is a prime.
It is not a weakly prime, because it can be changed into another prime (13405315159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702657576 + 6702657577.
It is an arithmetic number, because the mean of its divisors is an integer number (6702657577).
Almost surely, 213405315153 is an apocalyptic number.
It is an amenable number.
13405315153 is a deficient number, since it is larger than the sum of its proper divisors (1).
13405315153 is an equidigital number, since it uses as much as digits as its factorization.
13405315153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 13405315153 its reverse (35151350431), we get a palindrome (48556665584).
The spelling of 13405315153 in words is "thirteen billion, four hundred five million, three hundred fifteen thousand, one hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •