Base | Representation |
---|---|
bin | 11000111110000010… |
… | …01110000001101101 |
3 | 1021121020110120100212 |
4 | 30133001032001231 |
5 | 204423230041211 |
6 | 10054110232205 |
7 | 653124204356 |
oct | 143701160155 |
9 | 37536416325 |
10 | 13405315181 |
11 | 5759a50785 |
12 | 27214b5665 |
13 | 135835467b |
14 | 912514d2d |
15 | 536d1538b |
hex | 31f04e06d |
13405315181 has 2 divisors, whose sum is σ = 13405315182. Its totient is φ = 13405315180.
The previous prime is 13405315159. The next prime is 13405315211. The reversal of 13405315181 is 18151350431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9868634281 + 3536680900 = 99341^2 + 59470^2 .
It is a cyclic number.
It is not a de Polignac number, because 13405315181 - 26 = 13405315117 is a prime.
It is a super-2 number, since 2×134053151812 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13405315481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702657590 + 6702657591.
It is an arithmetic number, because the mean of its divisors is an integer number (6702657591).
Almost surely, 213405315181 is an apocalyptic number.
It is an amenable number.
13405315181 is a deficient number, since it is larger than the sum of its proper divisors (1).
13405315181 is an equidigital number, since it uses as much as digits as its factorization.
13405315181 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 32.
The spelling of 13405315181 in words is "thirteen billion, four hundred five million, three hundred fifteen thousand, one hundred eighty-one".
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