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13405422353443 = 19659768187319
BaseRepresentation
bin1100001100010011000101…
…1011111111110000100011
31202110112201221011222211121
43003010301123333300203
53224113301110302233
644302211020353111
72552336601632131
oct303046133776043
952415657158747
1013405422353443
1142a923149252a
1216060889a5797
137631837c2303
14344b7c3cc751
15183a8c11392d
hexc31316ffc23

13405422353443 has 4 divisors (see below), whose sum is σ = 13405490737360. Its totient is φ = 13405353969528.

The previous prime is 13405422353441. The next prime is 13405422353459. The reversal of 13405422353443 is 34435322450431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13405422353443 - 21 = 13405422353441 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13405422353443.

It is not an unprimeable number, because it can be changed into a prime (13405422353441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33897063 + ... + 34290256.

It is an arithmetic number, because the mean of its divisors is an integer number (3351372684340).

Almost surely, 213405422353443 is an apocalyptic number.

13405422353443 is a deficient number, since it is larger than the sum of its proper divisors (68383917).

13405422353443 is an equidigital number, since it uses as much as digits as its factorization.

13405422353443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68383916.

The product of its (nonzero) digits is 2073600, while the sum is 43.

The spelling of 13405422353443 in words is "thirteen trillion, four hundred five billion, four hundred twenty-two million, three hundred fifty-three thousand, four hundred forty-three".

Divisors: 1 196597 68187319 13405422353443