Base | Representation |
---|---|
bin | 1100001100010011000110… |
… | …0011100010011000111101 |
3 | 1202110112202001220102120120 |
4 | 3003010301203202120331 |
5 | 3224113302112032201 |
6 | 44302211131005153 |
7 | 2552336624504433 |
oct | 303046143423075 |
9 | 52415661812516 |
10 | 13405424330301 |
11 | 42a92326127a3 |
12 | 16060895997b9 |
13 | 763184035053 |
14 | 344b7c784d53 |
15 | 183a8c3a4536 |
hex | c31318e263d |
13405424330301 has 4 divisors (see below), whose sum is σ = 17873899107072. Its totient is φ = 8936949553532.
The previous prime is 13405424330203. The next prime is 13405424330317. The reversal of 13405424330301 is 10303342450431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13405424330301 - 29 = 13405424329789 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13405424330351) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2234237388381 + ... + 2234237388386.
It is an arithmetic number, because the mean of its divisors is an integer number (4468474776768).
Almost surely, 213405424330301 is an apocalyptic number.
It is an amenable number.
13405424330301 is a deficient number, since it is larger than the sum of its proper divisors (4468474776771).
13405424330301 is an equidigital number, since it uses as much as digits as its factorization.
13405424330301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4468474776770.
The product of its (nonzero) digits is 51840, while the sum is 33.
Adding to 13405424330301 its reverse (10303342450431), we get a palindrome (23708766780732).
The spelling of 13405424330301 in words is "thirteen trillion, four hundred five billion, four hundred twenty-four million, three hundred thirty thousand, three hundred one".
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