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134054296349 is a prime number
BaseRepresentation
bin111110011011001000…
…0100011101100011101
3110211000110210211122212
41330312100203230131
54144020344440344
6141330024450205
712453663501221
oct1746620435435
9424013724585
10134054296349
1151941178a76
1221b92619965
13c844b2705c
1466b9b14781
153748c6179e
hex1f36423b1d

134054296349 has 2 divisors, whose sum is σ = 134054296350. Its totient is φ = 134054296348.

The previous prime is 134054296241. The next prime is 134054296379. The reversal of 134054296349 is 943692450431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 133577092324 + 477204025 = 365482^2 + 21845^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134054296349 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 134054296297 and 134054296306.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134054296379) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67027148174 + 67027148175.

It is an arithmetic number, because the mean of its divisors is an integer number (67027148175).

Almost surely, 2134054296349 is an apocalyptic number.

It is an amenable number.

134054296349 is a deficient number, since it is larger than the sum of its proper divisors (1).

134054296349 is an equidigital number, since it uses as much as digits as its factorization.

134054296349 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2799360, while the sum is 50.

The spelling of 134054296349 in words is "one hundred thirty-four billion, fifty-four million, two hundred ninety-six thousand, three hundred forty-nine".