13405432535413 has 4 divisors (see below), whose sum is σ = 13413167928108. Its totient is φ = 13397697142720.

The previous prime is 13405432535359. The next prime is 13405432535431. The reversal of 13405432535413 is 31453523450431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8413143893764 + 4992288641649 = 2900542^2 + 2234343^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13405432535413 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13405432535413.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13405432595413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3867693748 + ... + 3867697213.

It is an arithmetic number, because the mean of its divisors is an integer number (3353291982027).

Almost surely, 2^{13405432535413} is an apocalyptic number.

It is an amenable number.

13405432535413 is a deficient number, since it is larger than the sum of its proper divisors (7735392695).

13405432535413 is an equidigital number, since it uses as much as digits as its factorization.

13405432535413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7735392694.

The product of its (nonzero) digits is 1296000, while the sum is 43.

Adding to 13405432535413 its reverse (31453523450431), we get a palindrome (44858955985844).

The spelling of 13405432535413 in words is "thirteen trillion, four hundred five billion, four hundred thirty-two million, five hundred thirty-five thousand, four hundred thirteen".