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134054626477 is a prime number
BaseRepresentation
bin111110011011001000…
…1110100010010101101
3110211000111102121111211
41330312101310102231
54144020441021402
6141330035514421
712453666344542
oct1746621642255
9424014377454
10134054626477
1151941384002
1221b92758a11
13c844c113b5
1466b9b9cbc9
153748cc94d7
hex1f364744ad

134054626477 has 2 divisors, whose sum is σ = 134054626478. Its totient is φ = 134054626476.

The previous prime is 134054626463. The next prime is 134054626499. The reversal of 134054626477 is 774626450431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 81765114916 + 52289511561 = 285946^2 + 228669^2 .

It is an emirp because it is prime and its reverse (774626450431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134054626477 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 134054626477.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134054626877) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67027313238 + 67027313239.

It is an arithmetic number, because the mean of its divisors is an integer number (67027313239).

Almost surely, 2134054626477 is an apocalyptic number.

It is an amenable number.

134054626477 is a deficient number, since it is larger than the sum of its proper divisors (1).

134054626477 is an equidigital number, since it uses as much as digits as its factorization.

134054626477 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3386880, while the sum is 49.

The spelling of 134054626477 in words is "one hundred thirty-four billion, fifty-four million, six hundred twenty-six thousand, four hundred seventy-seven".