Base | Representation |
---|---|
bin | 1100001100010011011000… |
… | …0101110011010001011011 |
3 | 1202110112221101002020200102 |
4 | 3003010312011303101123 |
5 | 3224113431101434321 |
6 | 44302222445530015 |
7 | 2552341540330013 |
oct | 303046605632133 |
9 | 52415841066612 |
10 | 13405500421211 |
11 | 42a9271563a48 |
12 | 16060aab7390b |
13 | 763196a27062 |
14 | 344b88910c43 |
15 | 183a93dd4c0b |
hex | c313617345b |
13405500421211 has 2 divisors, whose sum is σ = 13405500421212. Its totient is φ = 13405500421210.
The previous prime is 13405500421189. The next prime is 13405500421241. The reversal of 13405500421211 is 11212400550431.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13405500421211 is a prime.
It is not a weakly prime, because it can be changed into another prime (13405500421241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702750210605 + 6702750210606.
It is an arithmetic number, because the mean of its divisors is an integer number (6702750210606).
Almost surely, 213405500421211 is an apocalyptic number.
13405500421211 is a deficient number, since it is larger than the sum of its proper divisors (1).
13405500421211 is an equidigital number, since it uses as much as digits as its factorization.
13405500421211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4800, while the sum is 29.
Adding to 13405500421211 its reverse (11212400550431), we get a palindrome (24617900971642).
The spelling of 13405500421211 in words is "thirteen trillion, four hundred five billion, five hundred million, four hundred twenty-one thousand, two hundred eleven".
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