Base | Representation |
---|---|
bin | 1100001100010011011000… |
… | …1001101110011100100101 |
3 | 1202110112221110000111221111 |
4 | 3003010312021232130211 |
5 | 3224113431332400041 |
6 | 44302222523545021 |
7 | 2552341552143322 |
oct | 303046611563445 |
9 | 52415843014844 |
10 | 13405501450021 |
11 | 42a92720a69aa |
12 | 16060ab38b171 |
13 | 763196cc7415 |
14 | 344b88adbb49 |
15 | 183a94039981 |
hex | c313626e725 |
13405501450021 has 4 divisors (see below), whose sum is σ = 13405515742432. Its totient is φ = 13405487157612.
The previous prime is 13405501450001. The next prime is 13405501450049. The reversal of 13405501450021 is 12005410550431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13405501450021 - 217 = 13405501318949 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13405501450001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5632395 + ... + 7650808.
It is an arithmetic number, because the mean of its divisors is an integer number (3351378935608).
Almost surely, 213405501450021 is an apocalyptic number.
It is an amenable number.
13405501450021 is a deficient number, since it is larger than the sum of its proper divisors (14292411).
13405501450021 is a wasteful number, since it uses less digits than its factorization.
13405501450021 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14292410.
The product of its (nonzero) digits is 12000, while the sum is 31.
The spelling of 13405501450021 in words is "thirteen trillion, four hundred five billion, five hundred one million, four hundred fifty thousand, twenty-one".
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