Base | Representation |
---|---|
bin | 1100001100010011011000… |
… | …1011110111111110110001 |
3 | 1202110112221111002010200221 |
4 | 3003010312023313332301 |
5 | 3224113432003411421 |
6 | 44302222544013041 |
7 | 2552341560010603 |
oct | 303046613677661 |
9 | 52415844063627 |
10 | 13405502013361 |
11 | 42a9272451177 |
12 | 16060ab601181 |
13 | 763197163963 |
14 | 344b88c07173 |
15 | 183a940eb841 |
hex | c31362f7fb1 |
13405502013361 has 2 divisors, whose sum is σ = 13405502013362. Its totient is φ = 13405502013360.
The previous prime is 13405502013331. The next prime is 13405502013367. The reversal of 13405502013361 is 16331020550431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12697505982736 + 707996030625 = 3563356^2 + 841425^2 .
It is a cyclic number.
It is not a de Polignac number, because 13405502013361 - 211 = 13405502011313 is a prime.
It is not a weakly prime, because it can be changed into another prime (13405502013367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702751006680 + 6702751006681.
It is an arithmetic number, because the mean of its divisors is an integer number (6702751006681).
Almost surely, 213405502013361 is an apocalyptic number.
It is an amenable number.
13405502013361 is a deficient number, since it is larger than the sum of its proper divisors (1).
13405502013361 is an equidigital number, since it uses as much as digits as its factorization.
13405502013361 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32400, while the sum is 34.
Adding to 13405502013361 its reverse (16331020550431), we get a palindrome (29736522563792).
The spelling of 13405502013361 in words is "thirteen trillion, four hundred five billion, five hundred two million, thirteen thousand, three hundred sixty-one".
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