13405502013331 has 2 divisors, whose sum is σ = 13405502013332. Its totient is φ = 13405502013330.

The previous prime is 13405502013311. The next prime is 13405502013361. The reversal of 13405502013331 is 13331020550431.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13405502013331 - 2¹³ = 13405502005139 is a prime.

It is a super-2 number, since 2×13405502013331² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13405502013293 and 13405502013302.

It is not a weakly prime, because it can be changed into another prime (13405502013311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702751006665 + 6702751006666.

It is an arithmetic number, because the mean of its divisors is an integer number (6702751006666).

Almost surely, 2^{13405502013331} is an apocalyptic number.

13405502013331 is a deficient number, since it is larger than the sum of its proper divisors (1).

13405502013331 is an equidigital number, since it uses as much as digits as its factorization.

13405502013331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16200, while the sum is 31.

Adding to 13405502013331 its reverse (13331020550431), we get a palindrome (26736522563762).

The spelling of 13405502013331 in words is "thirteen trillion, four hundred five billion, five hundred two million, thirteen thousand, three hundred thirty-one".