Search a number
-
+
134055041 is a prime number
BaseRepresentation
bin1111111110110…
…00010010000001
3100100020200221112
413333120102001
5233304230131
621145133105
73215310011
oct777302201
9310220845
10134055041
116974159a
1238a8a195
1321a08413
1413b37c41
15bb8002b
hex7fd8481

134055041 has 2 divisors, whose sum is σ = 134055042. Its totient is φ = 134055040.

The previous prime is 134055011. The next prime is 134055049. The reversal of 134055041 is 140550431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 117072400 + 16982641 = 10820^2 + 4121^2 .

It is a cyclic number.

It is not a de Polignac number, because 134055041 - 210 = 134054017 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 134054998 and 134055016.

It is not a weakly prime, because it can be changed into another prime (134055049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67027520 + 67027521.

It is an arithmetic number, because the mean of its divisors is an integer number (67027521).

Almost surely, 2134055041 is an apocalyptic number.

It is an amenable number.

134055041 is a deficient number, since it is larger than the sum of its proper divisors (1).

134055041 is an equidigital number, since it uses as much as digits as its factorization.

134055041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1200, while the sum is 23.

The square root of 134055041 is about 11578.2140678086. The cubic root of 134055041 is about 511.7930491435.

The spelling of 134055041 in words is "one hundred thirty-four million, fifty-five thousand, forty-one".