Base | Representation |
---|---|
bin | 1100001100010011011001… |
… | …0011111000011101111111 |
3 | 1202110112221122000210012020 |
4 | 3003010312103320131333 |
5 | 3224113433023100021 |
6 | 44302223101011223 |
7 | 2552341613602560 |
oct | 303046623703577 |
9 | 52415848023166 |
10 | 13405504112511 |
11 | 42a9273655305 |
12 | 16060b0253b13 |
13 | 76319771a264 |
14 | 344b891d2167 |
15 | 183a943b37c6 |
hex | c31364f877f |
13405504112511 has 16 divisors (see below), whose sum is σ = 20732321927424. Its totient is φ = 7545955405824.
The previous prime is 13405504112509. The next prime is 13405504112519. The reversal of 13405504112511 is 11521140550431.
It is not a de Polignac number, because 13405504112511 - 21 = 13405504112509 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13405504112519) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4763859330 + ... + 4763862143.
It is an arithmetic number, because the mean of its divisors is an integer number (1295770120464).
Almost surely, 213405504112511 is an apocalyptic number.
13405504112511 is a deficient number, since it is larger than the sum of its proper divisors (7326817814913).
13405504112511 is an equidigital number, since it uses as much as digits as its factorization.
13405504112511 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9527721550.
The product of its (nonzero) digits is 12000, while the sum is 33.
Adding to 13405504112511 its reverse (11521140550431), we get a palindrome (24926644662942).
The spelling of 13405504112511 in words is "thirteen trillion, four hundred five billion, five hundred four million, one hundred twelve thousand, five hundred eleven".
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