Base | Representation |
---|---|
bin | 10011100000011111010… |
… | …001000010101100000011 |
3 | 11202011012112112021021011 |
4 | 103200133101002230003 |
5 | 133430423403420012 |
6 | 2503501524141351 |
7 | 165565121013001 |
oct | 23403721025403 |
9 | 4664175467234 |
10 | 1340554357507 |
11 | 477586a94232 |
12 | 197984b37857 |
13 | 9954bc846a1 |
14 | 48c5161ba71 |
15 | 24d0e4111a7 |
hex | 1381f442b03 |
1340554357507 has 2 divisors, whose sum is σ = 1340554357508. Its totient is φ = 1340554357506.
The previous prime is 1340554357501. The next prime is 1340554357517. The reversal of 1340554357507 is 7057534550431.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1340554357507 is a prime.
It is not a weakly prime, because it can be changed into another prime (1340554357501) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670277178753 + 670277178754.
It is an arithmetic number, because the mean of its divisors is an integer number (670277178754).
Almost surely, 21340554357507 is an apocalyptic number.
1340554357507 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340554357507 is an equidigital number, since it uses as much as digits as its factorization.
1340554357507 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4410000, while the sum is 49.
The spelling of 1340554357507 in words is "one trillion, three hundred forty billion, five hundred fifty-four million, three hundred fifty-seven thousand, five hundred seven".
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