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1340560223 is a prime number
BaseRepresentation
bin100111111100111…
…0101001101011111
310110102111111220122
41033321311031133
510221140411343
6341004505155
745135400562
oct11771651537
93412444818
101340560223
11628790812
12314b4b1bb
13184969802
14ca07c4d9
157ca53068
hex4fe7535f

1340560223 has 2 divisors, whose sum is σ = 1340560224. Its totient is φ = 1340560222.

The previous prime is 1340560189. The next prime is 1340560229. The reversal of 1340560223 is 3220650431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1340560223 - 28 = 1340559967 is a prime.

It is a super-2 number, since 2×13405602232 = 3594203422979619458, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1340560192 and 1340560201.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340560229) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670280111 + 670280112.

It is an arithmetic number, because the mean of its divisors is an integer number (670280112).

Almost surely, 21340560223 is an apocalyptic number.

1340560223 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340560223 is an equidigital number, since it uses as much as digits as its factorization.

1340560223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 26.

The square root of 1340560223 is about 36613.6616988796. The cubic root of 1340560223 is about 1102.6273896366.

The spelling of 1340560223 in words is "one billion, three hundred forty million, five hundred sixty thousand, two hundred twenty-three".