Base | Representation |
---|---|
bin | 11000111110000111… |
… | …11011100010101101 |
3 | 1021121021210200021211 |
4 | 30133003323202231 |
5 | 204423420312101 |
6 | 10054133354421 |
7 | 653133224422 |
oct | 143703734255 |
9 | 37537720254 |
10 | 13406025901 |
11 | 575a396754 |
12 | 2721798a11 |
13 | 1358543008 |
14 | 91265bd49 |
15 | 536e05c51 |
hex | 31f0fb8ad |
13406025901 has 2 divisors, whose sum is σ = 13406025902. Its totient is φ = 13406025900.
The previous prime is 13406025889. The next prime is 13406025929. The reversal of 13406025901 is 10952060431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10830564900 + 2575461001 = 104070^2 + 50749^2 .
It is a cyclic number.
It is not a de Polignac number, because 13406025901 - 233 = 4816091309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13406025931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6703012950 + 6703012951.
It is an arithmetic number, because the mean of its divisors is an integer number (6703012951).
Almost surely, 213406025901 is an apocalyptic number.
It is an amenable number.
13406025901 is a deficient number, since it is larger than the sum of its proper divisors (1).
13406025901 is an equidigital number, since it uses as much as digits as its factorization.
13406025901 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 31.
The spelling of 13406025901 in words is "thirteen billion, four hundred six million, twenty-five thousand, nine hundred one".
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