Base | Representation |
---|---|
bin | 10011100000100101111… |
… | …111010011011100110111 |
3 | 11202011111101202121212001 |
4 | 103200211333103130313 |
5 | 133431141242214322 |
6 | 2503521033440131 |
7 | 165600660506341 |
oct | 23404577233467 |
9 | 4664441677761 |
10 | 1340667148087 |
11 | 477634721493 |
12 | 1979b6870047 |
13 | 99569455c87 |
14 | 48c625bc291 |
15 | 24d19290827 |
hex | 13825fd3737 |
1340667148087 has 2 divisors, whose sum is σ = 1340667148088. Its totient is φ = 1340667148086.
The previous prime is 1340667148081. The next prime is 1340667148159. The reversal of 1340667148087 is 7808417660431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1340667148087 - 219 = 1340666623799 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1340667148081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670333574043 + 670333574044.
It is an arithmetic number, because the mean of its divisors is an integer number (670333574044).
Almost surely, 21340667148087 is an apocalyptic number.
1340667148087 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340667148087 is an equidigital number, since it uses as much as digits as its factorization.
1340667148087 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5419008, while the sum is 55.
The spelling of 1340667148087 in words is "one trillion, three hundred forty billion, six hundred sixty-seven million, one hundred forty-eight thousand, eighty-seven".
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