Base | Representation |
---|---|
bin | 111110011011100010… |
… | …0111010000011110111 |
3 | 110211001102122001012202 |
4 | 1330313010322003313 |
5 | 4144032403110242 |
6 | 141331234535115 |
7 | 12454221235235 |
oct | 1746704720367 |
9 | 424042561182 |
10 | 134068019447 |
11 | 519489a137a |
12 | 21b9713749b |
13 | c84792042b |
14 | 66bb887955 |
15 | 374a072932 |
hex | 1f3713a0f7 |
134068019447 has 2 divisors, whose sum is σ = 134068019448. Its totient is φ = 134068019446.
The previous prime is 134068019401. The next prime is 134068019453. The reversal of 134068019447 is 744910860431.
It is a strong prime.
It is an emirp because it is prime and its reverse (744910860431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134068019447 - 214 = 134068003063 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134068019647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67034009723 + 67034009724.
It is an arithmetic number, because the mean of its divisors is an integer number (67034009724).
Almost surely, 2134068019447 is an apocalyptic number.
134068019447 is a deficient number, since it is larger than the sum of its proper divisors (1).
134068019447 is an equidigital number, since it uses as much as digits as its factorization.
134068019447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 580608, while the sum is 47.
Adding to 134068019447 its reverse (744910860431), we get a palindrome (878978879878).
The spelling of 134068019447 in words is "one hundred thirty-four billion, sixty-eight million, nineteen thousand, four hundred forty-seven".
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