Base | Representation |
---|---|
bin | 11000111110010010… |
… | …01011010110001011 |
3 | 1021121101101120001120 |
4 | 30133021023112023 |
5 | 204424243320410 |
6 | 10054223050323 |
7 | 653151013455 |
oct | 143711132613 |
9 | 37541346046 |
10 | 13407401355 |
11 | 5760146097 |
12 | 27221409a3 |
13 | 13589050aa |
14 | 9128d92d5 |
15 | 5370c8570 |
hex | 31f24b58b |
13407401355 has 8 divisors (see below), whose sum is σ = 21451842192. Its totient is φ = 7150614048.
The previous prime is 13407401347. The next prime is 13407401383. The reversal of 13407401355 is 55310470431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13407401355 - 23 = 13407401347 is a prime.
It is a super-2 number, since 2×134074013552 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 446913364 + ... + 446913393.
It is an arithmetic number, because the mean of its divisors is an integer number (2681480274).
Almost surely, 213407401355 is an apocalyptic number.
13407401355 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13407401355 is a deficient number, since it is larger than the sum of its proper divisors (8044440837).
13407401355 is an equidigital number, since it uses as much as digits as its factorization.
13407401355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 893826765.
The product of its (nonzero) digits is 25200, while the sum is 33.
Adding to 13407401355 its reverse (55310470431), we get a palindrome (68717871786).
The spelling of 13407401355 in words is "thirteen billion, four hundred seven million, four hundred one thousand, three hundred fifty-five".
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