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13407401355 = 35893826757
BaseRepresentation
bin11000111110010010…
…01011010110001011
31021121101101120001120
430133021023112023
5204424243320410
610054223050323
7653151013455
oct143711132613
937541346046
1013407401355
115760146097
1227221409a3
1313589050aa
149128d92d5
155370c8570
hex31f24b58b

13407401355 has 8 divisors (see below), whose sum is σ = 21451842192. Its totient is φ = 7150614048.

The previous prime is 13407401347. The next prime is 13407401383. The reversal of 13407401355 is 55310470431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13407401355 - 23 = 13407401347 is a prime.

It is a super-2 number, since 2×134074013552 (a number of 21 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 446913364 + ... + 446913393.

It is an arithmetic number, because the mean of its divisors is an integer number (2681480274).

Almost surely, 213407401355 is an apocalyptic number.

13407401355 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

13407401355 is a deficient number, since it is larger than the sum of its proper divisors (8044440837).

13407401355 is an equidigital number, since it uses as much as digits as its factorization.

13407401355 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 893826765.

The product of its (nonzero) digits is 25200, while the sum is 33.

Adding to 13407401355 its reverse (55310470431), we get a palindrome (68717871786).

The spelling of 13407401355 in words is "thirteen billion, four hundred seven million, four hundred one thousand, three hundred fifty-five".

Divisors: 1 3 5 15 893826757 2681480271 4469133785 13407401355