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1340745148447 is a prime number
BaseRepresentation
bin10011100000101010101…
…000110110100000011111
311202011200211112110020021
4103200222220312200133
5133431321224222242
62503532501333011
7165602625503545
oct23405250664037
94664624473207
101340745148447
114776747572a1
12197a18a07167
139957c666133
1448c6cac3d95
1524d2104bb67
hex1382aa3681f

1340745148447 has 2 divisors, whose sum is σ = 1340745148448. Its totient is φ = 1340745148446.

The previous prime is 1340745148427. The next prime is 1340745148453. The reversal of 1340745148447 is 7448415470431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1340745148447 - 215 = 1340745115679 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1340745148394 and 1340745148403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340745148427) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670372574223 + 670372574224.

It is an arithmetic number, because the mean of its divisors is an integer number (670372574224).

Almost surely, 21340745148447 is an apocalyptic number.

1340745148447 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340745148447 is an equidigital number, since it uses as much as digits as its factorization.

1340745148447 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6021120, while the sum is 52.

The spelling of 1340745148447 in words is "one trillion, three hundred forty billion, seven hundred forty-five million, one hundred forty-eight thousand, four hundred forty-seven".