1340767673351 has 4 divisors (see below), whose sum is σ = 1340986366104. Its totient is φ = 1340548980600.

The previous prime is 1340767673347. The next prime is 1340767673383. The reversal of 1340767673351 is 1533767670431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1340767673351 - 2² = 1340767673347 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1340767673293 and 1340767673302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340767673251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 109337180 + ... + 109349441.

It is an arithmetic number, because the mean of its divisors is an integer number (335246591526).

Almost surely, 2^{1340767673351} is an apocalyptic number.

1340767673351 is a deficient number, since it is larger than the sum of its proper divisors (218692753).

1340767673351 is an equidigital number, since it uses as much as digits as its factorization.

1340767673351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 218692752.

The product of its (nonzero) digits is 6667920, while the sum is 53.

The spelling of 1340767673351 in words is "one trillion, three hundred forty billion, seven hundred sixty-seven million, six hundred seventy-three thousand, three hundred fifty-one".